Mega Code Archive
How to load a query result into a PHP Array
<![CDATA[
<?php
/* You can put this in other file and just include it */
function OpenDb($hostname,$uid,$pwd,$dbname){
$link = @mysql_pconnect($hostname,$uid,$pwd);
if($link && mysql_select_db($dbname)){
return($link);
}
else{
return(FALSE);
}
}
?>
<?php
function QueryIntoArray($query){
settype($retval,"array");
$result= mysql_query($query);
if(!$result){
print "Query Failed";
}
for($i=0;$i<mysql_numrows($result);$i++){
for($j=0;$j<mysql_num_fields($result);$j++){
$retval[$i][mysql_field_name($result,$j)] = mysql_result
($result,$i,mysql_field_name($result,$j));
}//end inner loop
}//end outer loop
return $retval;
}//end function
?>
<!--An Example How To Use The functions
To try it simple change the appropriate variable to your own database & tables
-->
<HTML>
<HEAD>
<TITLE>PHP Array Test</TITLE>
</HEAD>
<BODY BGCOLOR=WHITE>
<?php
OpenDb("myhost","myuid","mypwd","mydatabase") or die("Failed Opening Database");
settype($myresult,"array");
$query = "SELECT * FROM mytable";
$myresult = QueryIntoArray($query);
for($i=0;$i<count($myresult);$i++){
print $myresult[$i]["MyField1"];
print $myresult[$i]["MyField2"];
}
?>
</BODY>
</HTML>
]]>