Mega Code Archive
User-Defined Function to Determine a Leap Year
<![CDATA[
<?php
function is_leapyear($year = 2004) {
$is_leap = (!($year % 4) && (($year % 100) || !($year % 400)));
return $is_leap;
}
$answer = is_leapyear(2000);
if($answer) {
echo "2000 is a leap year<BR>";
} else {
echo "2000 is not a leap year.<BR>";
}
$answer = is_leapyear();
if($answer) {
echo "2003 is a leap year.<BR>";
} else {
echo "2003 is not a leap year.<BR>";
}
?>
]]>