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Categories / Oracle PLSQL / Hierarchical Query
 

Including Other Conditions in a Hierarchical Query

SQL> CREATE TABLE employee (   2    employee_id INTEGER,   3    manager_id INTEGER,   4    first_name VARCHAR2(10) NOT NULL,   5    last_name VARCHAR2(10) NOT NULL,   6    title VARCHAR2(20),   7    salary NUMBER(6, 0)   8  ); Table created. SQL> SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)   2                 values( 1         ,0            , 'James'  ,'Smith'  ,'CEO',800000); 1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)   2                 values( 2         , 1         ,'Ron'     ,'Johnson','Sales Manager',600000); 1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)   2                 values( 3         , 2         ,'Fred'    ,'Hobbs'  ,'Sales Person',200000); 1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)   2                 values( 4         , 1         ,'Susan'   ,'Jones'  ,'Support Manager',500000); 1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)   2                 values( 5         , 2         ,'Rob'     ,'Green'  ,'Sales Person', 40000); 1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)   2                 values( 6         , 4         ,'Jane'    ,'Brown'  ,'Support Person',45000); 1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)   2                 values( 7         , 4         ,'John'    ,'Grey'   ,'Support Manager',30000); 1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)   2                 values( 8         , 7         ,'Jean'    ,'Blue'   ,'Support Person',29000); 1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)   2                 values( 9         , 6         ,'Henry'   ,'Heyson' ,'Support Person',30000); 1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)   2                 values( 10        , 1         ,'Kevin'   ,'Black'  ,'Ops Manager',100000); 1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)   2                 values( 11        , 10        ,'Keith'   ,'Long'   ,'Ops Person',50000); 1 row created. SQL> SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)   2                 values( 12        , 10        ,'Frank'   ,'Howard' ,'Ops Person',45000); 1 row created. SQL> SQL> insert into employee (EMPLOYEE_ID, MANAGER_ID,FIRST_NAME,LAST_NAME,TITLE,SALARY)   2                 values( 13        , 10        ,'Doreen'  ,'Penn'   ,'Ops Person',47000); 1 row created. SQL> SQL> SQL> SQL> SQL> select * from employee; EMPLOYEE_ID MANAGER_ID FIRST_NAME LAST_NAME  TITLE                    SALARY ----------- ---------- ---------- ---------- -------------------- ----------           1          0 James      Smith      CEO                      800000           2          1 Ron        Johnson    Sales Manager            600000           3          2 Fred       Hobbs      Sales Person             200000           4          1 Susan      Jones      Support Manager          500000           5          2 Rob        Green      Sales Person              40000           6          4 Jane       Brown      Support Person            45000           7          4 John       Grey       Support Manager           30000           8          7 Jean       Blue       Support Person            29000           9          6 Henry      Heyson     Support Person            30000          10          1 Kevin      Black      Ops Manager              100000          11         10 Keith      Long       Ops Person                50000          12         10 Frank      Howard     Ops Person                45000          13         10 Doreen     Penn       Ops Person                47000 13 rows selected. SQL> SQL> SQL> -- Including Other Conditions in a Hierarchical Query SQL> SQL> SELECT LEVEL,   2   LPAD(' ', 2 * LEVEL - 1) || first_name || ' ' ||   3   last_name AS employee, salary   4  FROM employee   5  WHERE salary <= 50000   6  START WITH employee_id = 1   7  CONNECT BY PRIOR employee_id = manager_id;      LEVEL EMPLOYEE                      SALARY ---------- ------------------------- ----------          3      Rob Green                 40000          3      Jane Brown                45000          4        Henry Heyson            30000          3      John Grey                 30000          4        Jean Blue               29000          3      Keith Long                50000          3      Frank Howard              45000          3      Doreen Penn               47000 8 rows selected. SQL> SQL> SQL> SQL> SQL> drop table employee; Table dropped. SQL> SQL>