Mega Code Archive
GROUPING() Comes to the Rescue
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You use the GROUPING() function with an expression that might contain NULLs.
GROUPING() function returning value is only relevant when the value is NULL.
GROUPING() function returns 1 when the NULL represents a super aggregate.
GROUPING() function returns 0 when the NULL represents a group of NULLs in the base table.
CUBE Query and the GROUPING() function
10>
11> CREATE TABLE employee(
12> id INTEGER NOT NULL PRIMARY KEY,
13> first_name VARCHAR(10),
14> last_name VARCHAR(10),
15> salary DECIMAL(10,2),
16> start_Date DATETIME,
17> region VARCHAR(10),
18> city VARCHAR(20),
19> managerid INTEGER
20> );
21> GO
1> INSERT INTO employee VALUES (1, 'Jason' , 'Martin', 5890,'2005-03-22','North','Vancouver',3);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (2, 'Alison', 'Mathews',4789,'2003-07-21','South','Utown',4);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (3, 'James' , 'Smith', 6678,'2001-12-01','North','Paris',5);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (4, 'Celia' , 'Rice', 5567,'2006-03-03','South','London',6);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (5, 'Robert', 'Black', 4467,'2004-07-02','East','Newton',7);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (6, 'Linda' , 'Green' , 6456,'2002-05-19','East','Calgary',8);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (7, 'David' , 'Larry', 5345,'2008-03-18','West','New York',9);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (8, 'James' , 'Cat', 4234,'2007-07-17','West','Regina',9);
2> GO
(1 rows affected)
1> INSERT INTO employee VALUES (9, 'Joan' , 'Act', 6123,'2001-04-16','North','Toronto',10);
2> GO
(1 rows affected)
1>
2> select * from employee;
3> GO
id first_name last_name salary start_Date region city managerid
----------- ---------- ---------- ------------ ----------------------- ---------- -------------------- -----------
1 Jason Martin 5890.00 2005-03-22 00:00:00.000 North Vancouver 3
2 Alison Mathews 4789.00 2003-07-21 00:00:00.000 South Utown 4
3 James Smith 6678.00 2001-12-01 00:00:00.000 North Paris 5
4 Celia Rice 5567.00 2006-03-03 00:00:00.000 South London 6
5 Robert Black 4467.00 2004-07-02 00:00:00.000 East Newton 7
6 Linda Green 6456.00 2002-05-19 00:00:00.000 East Calgary 8
7 David Larry 5345.00 2008-03-18 00:00:00.000 West New York 9
8 James Cat 4234.00 2007-07-17 00:00:00.000 West Regina 9
9 Joan Act 6123.00 2001-04-16 00:00:00.000 North Toronto 10
(9 rows affected)
1>
2>
3>
4> SELECT
5> ID,
6> GROUPING(ID) AS Grp_Cust,
7> YEAR(Start_Date) AS Order_Year,
8> GROUPING(YEAR(Start_Date)) AS Grp_Year,
9> COUNT(*) as Order_Count
10> FROM
11> Employee
12> GROUP BY
13> ID,
14> YEAR(Start_Date)
15> WITH CUBE
16> GO
ID Grp_Cust Order_Year Grp_Year Order_Count
----------- -------- ----------- -------- -----------
1 0 2005 0 1
1 0 NULL 1 1
2 0 2003 0 1
2 0 NULL 1 1
3 0 2001 0 1
3 0 NULL 1 1
4 0 2006 0 1
4 0 NULL 1 1
5 0 2004 0 1
5 0 NULL 1 1
6 0 2002 0 1
6 0 NULL 1 1
7 0 2008 0 1
7 0 NULL 1 1
8 0 2007 0 1
8 0 NULL 1 1
9 0 2001 0 1
9 0 NULL 1 1
NULL 1 NULL 1 9
NULL 1 2001 0 2
NULL 1 2002 0 1
NULL 1 2003 0 1
NULL 1 2004 0 1
NULL 1 2005 0 1
NULL 1 2006 0 1
NULL 1 2007 0 1
NULL 1 2008 0 1
(27 rows affected)
1>
2> drop table employee;
3> GO
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