Mega Code Archive

 

Categories / Java / Servlets

 

Send XML

import java.io.BufferedInputStream; import java.io.IOException; import java.io.PrintWriter; import java.net.MalformedURLException; import java.net.URL; import java.net.URLConnection; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; public class ResourceServlet extends HttpServlet {   public void doGet(HttpServletRequest request, HttpServletResponse response)       throws ServletException, IOException {     //get web.xml for display by a servlet     String file = "/WEB-INF/web.xml";     URL url = null;     URLConnection urlConn = null;     PrintWriter out = null;     BufferedInputStream buf = null;     try {       out = response.getWriter();       url = getServletContext().getResource(file);       //set response header       response.setContentType("text/xml");       urlConn = url.openConnection();       //establish connection with URL presenting web.xml       urlConn.connect();       buf = new BufferedInputStream(urlConn.getInputStream());       int readBytes = 0;       while ((readBytes = buf.read()) != -1)         out.write(readBytes);     } catch (MalformedURLException mue) {       throw new ServletException(mue.getMessage());     } catch (IOException ioe) {       throw new ServletException(ioe.getMessage());     } finally {       if (out != null)         out.close();       if (buf != null)         buf.close();     }   }   public void doPost(HttpServletRequest request, HttpServletResponse response)       throws ServletException, IOException {     doGet(request, response);   } }