Mega Code Archive
Use a wildcard
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class Stats<T extends Number> {
T[] nums;
Stats(T[] o) {
nums = o;
}
double average() {
double sum = 0.0;
for (int i = 0; i < nums.length; i++)
sum += nums[i].doubleValue();
return sum / nums.length;
}
boolean sameAvg(Stats<?> ob) {
if (average() == ob.average())
return true;
return false;
}
}
class WildcardDemo {
public static void main(String args[]) {
Integer inums[] = { 1, 2, 3, 4, 5 };
Stats<Integer> iob = new Stats<Integer>(inums);
double v = iob.average();
System.out.println("iob average is " + v);
Double dnums[] = { 1.1, 2.2, 3.3, 4.4, 5.5 };
Stats<Double> dob = new Stats<Double>(dnums);
double w = dob.average();
System.out.println("dob average is " + w);
Float fnums[] = { 1.0F, 2.0F, 3.0F, 4.0F, 5.0F };
Stats<Float> fob = new Stats<Float>(fnums);
double x = fob.average();
System.out.println("fob average is " + x);
// See which arrays have same average.
System.out.print("Averages of iob and dob ");
if (iob.sameAvg(dob))
System.out.println("are the same.");
else
System.out.println("differ.");
System.out.print("Averages of iob and fob ");
if (iob.sameAvg(fob))
System.out.println("are the same.");
else
System.out.println("differ.");
}
}
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