Mega Code Archive

 
Categories / Java Tutorial / Servlet
 

Generate Servlet Exception

import java.io.*; import javax.servlet.*; import javax.servlet.http.*; public class MyServlet extends HttpServlet {       public void init(ServletConfig config) throws ServletException {    super.init(config);    throw new NullPointerException();   }   public void doGet (HttpServletRequest req, HttpServletResponse res)                               throws IOException, ServletException   {     ServletOutputStream out = res.getOutputStream();     res.setContentType("text/html");     out.println("<html><head><title>Exception Thrower</title></head>");     out.println("<body>You'll never see this!</body></html>");   } } <?xml version="1.0" encoding="ISO-8859-1"?> <!DOCTYPE web-app     PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.2//EN"     "http://java.sun.com/j2ee/dtds/web-app_2_2.dtd"> <web-app>     <servlet><servlet-name>MyServletName</servlet-name>              <servlet-class>MyServlet</servlet-class>                   </servlet>          <servlet-mapping><servlet-name>MyServletName</servlet-name>         <url-pattern>/index.html</url-pattern>     </servlet-mapping> </web-app>