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Show window based on button name

<Window x:Class="LayoutPanels.Window1"     xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"     xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"     Title="Menu" Height="375.2" Width="252">     <Grid>       <StackPanel Margin="5" Button.Click="ButtonClick">         <Button>SimpleStack</Button>         <Button>SimpleWrap</Button>         <Button>SimpleDock</Button>         <Button>BasicDialogBox</Button>         <Button>SimpleGrid</Button>         <Button>SplitWindow</Button>         <Button>DoubleSplitWindow</Button>         <Button>SharedSizeGroup</Button>         <Button>SimpleCanvas</Button>         <Button>SimpleInkCanvas</Button>         <Button>TheUniformGrid</Button>         <Button>TextBoxColumn</Button>         <Button>LocalizableText</Button>         <Button>ModularContent</Button>       </StackPanel>              </Grid> </Window> //File:Window.xaml.cs using System; using System.Windows; using System.Windows.Controls; using System.Windows.Data; using System.Windows.Documents; using System.Windows.Media; using System.Windows.Media.Imaging; using System.Windows.Shapes; using System.Reflection; namespace LayoutPanels {     public partial class Window1 : Window     {         public Window1()         {             InitializeComponent();         }         private void ButtonClick(object sender, RoutedEventArgs e)         {             Button cmd = (Button)e.OriginalSource;                              Type type = this.GetType();             Assembly assembly = type.Assembly;                                    Window win = (Window)assembly.CreateInstance("YourNameSpace." + cmd.Content);             win.ShowDialog();         }     } }